Unit 2: Force and Translational Dynamics

1. Newton's Laws of Motion

Newton's laws form the foundation of classical mechanics and provide the framework for understanding force and motion.

First Law (Law of Inertia)

An object remains at rest or in uniform motion unless acted upon by a net external force.

Second Law

ΣF = ma

where:

Third Law

For every action force, there is an equal and opposite reaction force.

Example:

A 2 kg block is pushed with a force of 10 N. If friction is 2 N, calculate the acceleration.

Solution:
Net force = 10 N - 2 N = 8 N
a = F/m = 8 N/2 kg = 4 m/s²

2. Types of Forces

Gravitational Force

Fg = mg

where g = 9.81 m/s² on Earth

Normal Force

The perpendicular force exerted by a surface on an object.

Friction

Static Friction: fs ≤ μsN

Kinetic Friction: fk = μkN

where:

3. Free Body Diagrams

Free body diagrams (FBDs) are essential tools for visualizing and analyzing forces acting on objects.

Key Components:

Remember: The length of force arrows should be proportional to the magnitude of the forces!

4. Force Resolution and Components

Vector Components

Fx = F cos θ

Fy = F sin θ

Net Force Calculations

ΣFx = max

ΣFy = may

5. Applications of Newton's Second Law

Inclined Planes

Parallel component of weight: mg sin θ

Perpendicular component of weight: mg cos θ

Example:

A 5 kg block slides down a 30° incline. Calculate the acceleration if μk = 0.2.

Solution:
mg sin θ = 5(9.81)(sin 30°) = 24.525 N down slope
N = mg cos θ = 5(9.81)(cos 30°) = 42.47 N
fk = μkN = 0.2(42.47) = 8.494 N
Net force = 24.525 - 8.494 = 16.031 N
a = 16.031/5 = 3.21 m/s²

6. Tension and Connected Objects

Key Concepts:

For an Atwood machine:

T - m₁g = m₁a

m₂g - T = m₂a

7. Circular Motion Forces

Centripetal Force

Fc = mv²/r = mω²r

where:

Centripetal force is not a new type of force - it's provided by friction, tension, or normal force!

8. Spring Forces and Hooke's Law

Fs = -kx

where:

Example:

A 0.5 kg mass is attached to a spring with k = 20 N/m. If stretched 0.1 m, what is the acceleration?

Solution:
F = -kx = -20(0.1) = -2 N
a = F/m = -2/0.5 = -4 m/s²

9. Work-Energy and Forces

Work Done by Forces

W = F·d = Fd cos θ

Work-Energy Theorem: W = ΔKE = ½mv² - ½mv₀²

Conservative vs Non-conservative Forces

10. Momentum and Impulse

p = mv

F·Δt = Δp (Impulse-Momentum Theorem)

Applications:

For AP Physics C, you should be able to: